n^2-2.5n=5.41

Solution for n^2-2.5n=5.41 equation:

n^2-2.5n=5.41

We move all terms to the left:

n^2-2.5n-(5.41)=0

We add all the numbers together, and all the variables

n^2-2.5n-5.41=0

a = 1; b = -2.5; c = -5.41;
Δ = b2-4ac
Δ = -2.52-4·1·(-5.41)
Δ = 27.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{27.89}}{2*1}=\frac{2.5-\sqrt{27.89}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{27.89}}{2*1}=\frac{2.5+\sqrt{27.89}}{2}
$